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16x^2=3(8x-4)
We move all terms to the left:
16x^2-(3(8x-4))=0
We calculate terms in parentheses: -(3(8x-4)), so:We get rid of parentheses
3(8x-4)
We multiply parentheses
24x-12
Back to the equation:
-(24x-12)
16x^2-24x+12=0
a = 16; b = -24; c = +12;
Δ = b2-4ac
Δ = -242-4·16·12
Δ = -192
Delta is less than zero, so there is no solution for the equation
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